Re: A mathematical difficulty
The area of a sphere of that size would be for simplistic sake:
(60*60*24*365/2) = 1/2 light year (It's off a bit)
The area of the sphere would be that squared x 4 x pi, so
(60*60*24*365/2) * (60*60*24*365/2) * 4 * 3.14 = 3,122,790,589,440,000
which is the area of the sphere in number of light seconds. So yea, there would be a few of them...
Oh, a light second is 299,792,458 meters